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4x^2-47x-130=0
a = 4; b = -47; c = -130;
Δ = b2-4ac
Δ = -472-4·4·(-130)
Δ = 4289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-\sqrt{4289}}{2*4}=\frac{47-\sqrt{4289}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+\sqrt{4289}}{2*4}=\frac{47+\sqrt{4289}}{8} $
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